An electric heater rated ‘2.2 kW, 220 V’ is operated for 2 hours. Calculate:
i. Safe current
ii. Cost of electricity @ Rs. 5.20/ unit
Answers
Answer:
Power is energy consumed per unit time.
Here, energy consumed=P=2kW=2000W and time=t=10hr=36000s
P=
t
E
⟹E=Pt=2kW×10h=20kWh=20units
Since 1unit=1kWh
Cost=20×350=Rs7000
Given,
P = 2.2 kW = 2200 W
220 V is operated in 2 hours
To find,
i. Safe current
ii. Cost of electricity @ Rs. 5.20/ unit
Solution,
i) We will calculate the safe current with the help of the formula which is given below:
I = P/V
Putting the values in the formula:
We will get, I = 2200W/220V
I = 10 A
ii) For calculating the cost of electricity will first calculate the electrical energy consumed
Its formula is given below:
The electrical energy consumed = power × time
Putting the values in the formula:
The electrical energy consumed = 2.2 kW × 2 h
The electrical energy consumed = 4.4 kWh
The cost of electricity = 4.4 kWh × Rs. 5.2
The cost of electricity= Rs. 22.88
Hence, the safe current is 10 A and the cost of electricity is Rs. 22.88