Physics, asked by mallahaswanth2540, 1 year ago

An electric heater rated 880W operates 6h/day. Find the coat of energy to operate it for 30 days at Rs 3.00 per unit.

Answers

Answered by Anonymous
20

\huge\underline\blue{\sf Answer:}

\red{\boxed{\sf Cost\:of\: Energy\:is\:Rs.475.2 }}

\huge\underline\blue{\sf Solution:}

\large\underline\pink{\sf Given: }

  • Power (P) = 880W

  • Days = 30 days

  • Time = 6h/day

  • Price per unit = Rs. 3

\large\underline\pink{\sf To\:Find: }

  • Cost of Energy to operate 30 days = ?

━━━━━━━━━━━━━━━━━━━━━━━━━

We know that ,

{\boxed{\sf Energy=Power×Time }}

\large\implies{\sf E=880×6 }

\large\implies{\sf E= 5280 }

\large\implies{\sf E=5.28kwh\:or\:5.28\:unit }

For 30 days :-

\large\implies{\sf E=5.28×30 }

\large\implies{\sf E=158.4kwh\:158.4\:unit}

Price per unit is Rs. 3

So ,

\large\implies{\sf 158.4×3 }

\large\implies{\sf Rs.475.2 }

Hence ,

\red{\boxed{\sf Cost\:of\: Energy\:is\:Rs.475.2 }}

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