Question

An electric heater supplies heat to a system at a rate of 100 J/s. If the system performs work at a rate of 75 J/s, calculate the internal energy is increased​

Answer 1

Topic - Thermodynamics

We are provided that the heat supplied is 100 J/s, Work done is 75 J/s and we are supposed to find the internal energy increased.

According to the first law of thermodynamics:-

$\\\quad\bullet\quad\underline{\boxed{\bf Q = U+W}}\bigstar$

where, Q, U and W are Heat supplied, Internal energy and Work done respectively.

Now, simply substitute all the given values in the expression and you'll get the answer directly.

⇒ Q = U + W

⇒ U = Q - W

⇒ U = 100 - 75

⇒ U = 25 J/S

∴ 25 W is required answer.

______________________________