An electric heater supplies heat to a system at a rate of If system performs work at a rate of 75 joules per second. At what rate is the internal energy increasing?
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you question is lacked , A complete question is ------> An electric heater supplies heat to a system at a rate of 100W. If system performs work at a rate of 75 joules per second. At what rate is the internal energy increasing?
solution :- given, heat supplies to a system at a rate of 100W. so, Heat supplies to the system in a second, ∆H = 100J
and system performs work at the rate of 75J/sec. so, work done performed by system in a second , W = 75J
now, from first law of thermodynamics,
∆H = ∆U + W
where, ΔQ is the heat supplied to the system, W is the work done by the system and ΔU is the change in internal energy of the system.
∆U = ∆H - W = 100J - 75J = 25J
hence, internal energy increases of the system in a second = 25J
so, 25 J/sec is the rate of increasing internal energy.
solution :- given, heat supplies to a system at a rate of 100W. so, Heat supplies to the system in a second, ∆H = 100J
and system performs work at the rate of 75J/sec. so, work done performed by system in a second , W = 75J
now, from first law of thermodynamics,
∆H = ∆U + W
where, ΔQ is the heat supplied to the system, W is the work done by the system and ΔU is the change in internal energy of the system.
∆U = ∆H - W = 100J - 75J = 25J
hence, internal energy increases of the system in a second = 25J
so, 25 J/sec is the rate of increasing internal energy.
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