Question

An electric heater supplies heat to a system of gas at a rate of 150W. The system
performs work at a rate of 50J/s. At what rate is the internal energy increasing?​

Answer 1

Answer:

3Ω

Explanation:

H= I Rt

R = 50× 3÷50

=150÷50

=3Ω

Answer 2

Answer:

100W

Explanation:

Heat is supplied to the system at a rate of 100 W.

∴Heat supplied, Q = 150 J/s

The system performs at a rate of 50 J/s.

∴Work done, W = 50 J/s

From the first law of thermodynamics, we have:

Q = U + W

Where,

U = Internal energy

∴U = Q – W

= 150 – 50

= 100 J/s

= 100 W

Therefore, the internal energy of the given electric heater increases at a rate of 100 W.

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