Question

an electric heater uses 600 kj of electrical energy in 5 minutes .calculate its power rating

Answer 1

Work = 600kJ
         = 600000J

Time = 5 minutes
        = 5 x 60= 300 seconds

Power =  Work/Time
           =  600000/300
           =   2000 W or 2kW 

Answer 2

Explanation:

Here is your answer

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