An electric heater which is connected to a 220v supply line has two resistance coil A and B of 24ohm resistance each. these coils can be used separately in series or in parallel. calculte the current drawn when:
a) only one coil A is used
b) coils A and B are used in series
c)coils A and B are used in parallel
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Answer:
Given V=220 V
RA = RB = 24 ohm
(a) Current drawn when only coil A is used:
I = V/RA = 220/24
=9.16 amps
(b) Current drawn when coils A and B are used in series:
Total resistance, R = RA + RB = 24 + 24 = 48 ohms
I = V/R = 220/48
= 4.58 amps
(c) Current drawn when coils A and B are used in parallel:
Total resistance, 1/R = 1/RA + 1/RB = 1/24 + 1/24 = 2/24 = 1/12
R=12 ohms
I = V/R = 220/12
=18.33 amps
Explanation:
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