Question

An electric heater works in a 230V supply which draws a current of 5A for 3 minutes. Find out the quantity of heat produced in the heater. Also find out the resistance of the coil in the heater

Answer 1

Given
V=230v
I=5A
t=3min=180s
H=?
R=?

V=IR
R=V/I
R=230/5
R=46ohms
H=I^2Rt
H=(5)^2*46*180
H=207000J
H=207KJ

Answer 2

GIVEN :-

• Voltage of the electric heater , V = 230V

• Current of the electric heater , I = 5A

• Time , t = 3 × 60 seconds

TO FIND :-

• Heat produced in the heater .

• Resistance of the coil in the heater .

SOLUTION :-

• Formula to find heat , H = VIT

              Heat = 230 × 5  × 3  × 60

                       = 207000 J

• We know that , V = IR

     

              Resistance , $\sf R=\dfrac{V}{I}$

                                      $\sf = \dfrac{230}{5}$

                                      $\bf = 46 \ \Omega$

 

• Heat produced in the heater = 20700 J

• Resistance of the coil in the heater = 46 Ω