An electric heating pad rated at 110 V and 55 W is to be used at a 220 V source. It is proposed to connect the heating pad in series with a series-parallel combination of light bulbs, each rated at 100 V ; bulbs are having ratings of 25 W, 60 W, 75 W and 100 W. Obtain a possible scheme of the pad-bulbs combination. At what rate will heat be produced by the pad with this modification?
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heating pad voltage
The power dissipated by an electric bulb is given as P = VI.
In this case, Power P = 100 W and Voltage V = 220 V.
So, current I is I = P/V = 100/220 = 0.45 A.
When the supplied voltage is 110 V, the power consumed will be P=VI = 110 * 0.45 = 50 W.
Hence, the power consumed when operated at 110 V is 50 W.
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Answer:
heating pad voltage
Explanation:
The power dissipated by an electric bulb is given as P=VI
In the case Power P= 100W and voltage V =220W
So current I is I = P/V =100W /220W =0.45 A
when the supplied voltage is 110W the power consumed will be P/VI=110*0.45= 50W.
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