Question

an electric heats of power 2kw is connected to 230v supply. calculate the heat developed where this device works for 1800s? ​

Answer 1

• ??????????????(•~•).....}{{/;;:''"~?~~||₹__-++×÷==()(**&&^^%%$$@@!112333444555666778890℃°®©©\◆◆】】【【♀♂♂¶℅℅™™∆••`√££¢¢€¥¥¥¡¡¿¿[[]]]099877554311

Answer 2

Explanation:

3.6×10^6 joules

heat energy developed= power × time

= 2×10^3×1800=3.6×10^6 J