Question

An electric installation consists of 100 lamps each
drawing 0.2A at 220V Supply. Find the cost of working
of the installation for a month of 30 day at
5 hours per day if energy is charged at the rate of
₹2 per month​

Answer 1

Explanation:

total current consumed by 100bulb= 100*0.2

=20A

power consumed=vi

=20*220

=4400w

energy dissipated= 4400*30*5

=660000

=660units

cost = 660*2

=RS 1320

PLS mark as BRAINLIEST

Answer 2

Concept Introduction: Current is the basic concept of Physics.

Given:

We have been Given: No. of Lamps is

$100$

Current drawing each lamp is

$0.2a$

Voltage supply is

$220volts$

Time is

$30 \times 5 = 150hrs$

Cost of each unit

$rs.2$

To Find:

We have to Find: Total cost of the working installation.

Solution:

According to the problem, Total current used is

$i_{total} = 100 \times 0.2 = 20amperes$

Total Power of the installation is

$p_{total} = v \times i \\ p_{total} = 20 \times 220 = 4400watts$

Therefore total energy dissipated is

$energy_{total} = 4400 \times 150 = 660000$

therefore the total energy is

$660 \: units$

therefore, total cost is

$660 \times 2 =rs.1320$

Final Answer: The total cost is

$rs.1320$

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