an electric iron box of resistance 20 volt consumer a current of 5 ampemeter calculate the heat developed in 30 seconds
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Answer:
v=20 volts
i=5ammeter
p=v×i
p=20×5
p=100watt
p=100/1000kilowatt
p=0.1kw
t=30sec
t=0.00833hours
e=p×t
e=0.1×0.00833
e=0.000833kwh
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