an electric iron consume energy at rate of 150 watt. when heating is at the maximum rate and 250 watt when the heating is at the minimum. the voltage is 110 watt. what is the current and the resistance in each case?
Answers
Answered by
0
Answer:
366 & 250
section -A
367 Ω and
250Ω
Explanation:
When heating is maximum:
power= 150watt
V= 250volt
we know that P=VI
=> 150= 250×I
=> I= 3/5 ampere
R=V/I = 220/(3/5)= 366.67Ω
When heating is minimum
power= 250watt
V=250
=> P= VI
=> 110= 250×I
=> I= 250/250= 1 ampere
R=V/I= 250/1= 250 Ω
hope it will help you
mark me as a brainliest
followe thank you.
Similar questions