Question

An electric iron consumes 1500 watt of electric power when it is operated at 220 volt. Then what is the rating of fuse must be?​

Answer 1

Answer:

p= vi

1500/220=6.8

therefore the rating of fuse should be 7 or 8A

Answer 2

The rating of fuse must be 6.9 A.

Explanation:

Given that,

Power consumed by the electric iron, P = 1500 watts

Voltage of the iron, V = 220 volts

We need to find the rating of fuse. We know that the power of an electrical appliance is given by :

P = V I

I is the current rating of the fuse

So,

$I=\dfrac{P}{V}$

$I=\dfrac{1500\ W}{220\ V}$

I = 6.818 A

or

I = 6.9 A

So, the rating of fuse must be 6.9 A. Hence, this is the required solution.

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