An electric iron consumes energy at a rate of 840 watt when heating is at the maximum rate and 360 watt when the heating is at the minimum. The voltage is 220 volt. What are the currents and the resistance im each case?
Answers
Answered by
4
Answer:
Explanation:
When heating at max rate,
power, P = 840W
V = 220V
We know P = VI
⇒ 840 = 220 × I
⇒ I = 840/220
⇒ I = 4 A
R = V/I = 220/4 = 55 Ω
So current = 4A and resistance = 55Ω
When heating at minimum rate,
power, P = 360W
V = 220V
We know P = VI
⇒ 360 = 220 × I
⇒ I = 360/220
⇒ I = 1.636 A
R = V/I = 220/1.636 = 134.45 Ω
So current = 1.636A and resistance = 134.45Ω
Similar questions
Computer Science,
5 months ago
English,
5 months ago
Math,
11 months ago
Computer Science,
1 year ago
Math,
1 year ago