Question

An electric iron consumes energy at a rate of 840W when heating it at maximum rate and 360 W when heated it at minimum .The applied voltage is 220V .What is the value of current and the resistance in each case?

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Answer 1

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Answer:

In first case power is 840 w

p= v*i

i= p/v= 840/220

i= 3.82 A

nd r= 220/3.82

in second case

i=360/220=1.64

r=220/1.64

Answer 2

Answer:

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