Question

An electric iron consumes energy at a rate of 840W when heating is at the maximum rate and 360W when the heating is at the minimum rate. The applied voltage is 220V. What is the value of current and resistance in each case?

Answer 1

energy rate = power in watt. case1. using the relation, P= I.V , 840= I.220, = I =840/220=2.1amp nd resis,v= i.r,220= 2.1.r , r= 220/2.1, = 104 case2: 360= I.220, I= 360/220= i= 1.6 nd resis = ,v= i.r 220= 1.6 . r, r = 220/ 1. 6,= 137, not sure but this may be The sol.