Question

An electric iron consumes energy at rate of 420w when heating is at maximum rate and 180 w when heating is at minimum. The voltage is 220V .What is the current and resistant in each case?

Answer 1

P = VI
then,
I = P/V
when heating is at maximum
current:
I = 420W/220V
=1.9(approx)
resistance:
R = V/I
= 220V/1.9A
=115.78(approx)
when heating in minimum
current:
I = P/V
= 180W/220V
= 0.81 (approx)
resistance:
R = V/I
=220V/0.81A
=271.60 (approx)

Answer 2

P = VI

then,

I = P/V

when heating is at maximum

current:

I = 420W/220V

=1.9(approx)

resistance:

R = V/I

= 220V/1.9A

=115.78(approx)

when heating in minimum

current:

I = P/V

= 180W/220V

= 0.81 (approx)

resistance:

R = V/I

=220V/0.81A

=271.60 (approx)

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