Question

An electric iron consumes energy at
the rate of 420 W when heating is at the
maximum rate and 180 W when heating is
at the minimum rate. The applied voltage is
220 V. What is the current in each case?​

Answer 1

Answer:

given

Pmax=420 W

Pmin=180W

V=220v

find =??

Imax=?

Imin=?

Explanation:

p=vi

Soo

Pmax=V×Imax

420 =220×Imax

420/220=Imax

1.9 A =Imax

Pmin =V × Imin

180 =220 ×Imin

180/220 =Imin

0.81A =Imin

Answer 2

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