an electric iron consumes energy at the rate of 420 what when heating is at maximum rate and 180 watt when heating is at minimum the voltage is 220 volt what is the current in and resistance in each case
Answers
Answered by
6
Answer:
Power minimum=180w
V^2/R=180
R=(220*220)/180
R=268.9ohm
Current,I=V/R=11/9 amp
For maximum power,
R=268.9 ohm
P=I^2R
I=rootP/R
I=root420/R
I=1.6 amp
amarraj79:
welcome
Similar questions