Question

An electric iron consumes energy at the rate of 880 W when heating is at the maximum rate and 440 W. when the heating at the minimum rate. the applied voltage is 220 . calculate the current and resistance in each case

Answer 1

Given :
Power at maximum rate =P=880W
voltage =V=220volts.
We know that P=V²/R
R=V²/P
⇒220x220/880
⇒48400/880
⇒55ohms
Maximum current I is
P=IV
I=P/V
=880/220
=4A
ii)power at minimum rate is 440W
voltage =V=220volts.
We know that P=V²/R
R=V²/P
⇒220x220/440
⇒48400/440
≈19ohms
Current at minimum rate is ,
P=IV
I=P/V
⇒440/220
⇒2A

Answer 2

this is the correct answer!!!!!
Hope it helps you out:-)