Question

An electric iron consumes energy at the rate of (a) 840 W when heating is at the maximum
360 W when the heating is at the minimum. The voltage is 220 V. What are the current and the
each case?

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Answer 1

Answer: P=VI

I= P/V

Explanation:

IN FIRST CASE = 840/220=3.8A

IN 2ND CASE =360/220==1.6A

Answer 2

Answer: P=VI

I= P/V

Explanation:

IN FIRST CASE = 840/220=3.8A

IN 2ND CASE =360/220==1.6A

Answer 3

Answer: P=VI

I= P/V

Explanation:

IN FIRST CASE = 840/220=3.8A

IN 2ND CASE =360/220==1.6A