An electric iron desiged for 110 v a.C. Supply was rated at 500 w. It was put across a 220 v supply. Assuming that at 110 v it supplied 500 w output, (i.E., no losses) at the new voltage it will supply
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p = v.i (50 / 11 A) 500/110
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Answer:
P=v²/r
500=110*110/R
R=24.2
P=220*220/24.2
P=2000W
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