Question

An electric iron draws 2.2 amperes of current from a 220 v.find resistance and power

Answer 1

Given:

• Current,I = 2.2 Amperes

• Potential differenc,V = 220 volt

To be calculated:

Calculate the Resistance,R and Power,P ?

Formula used:

• V = IR

• P = I²R

Solution:

We know the current and potential difference. So,we can calculate the resistance and power by using the formula:

V = IR

★ Putting the value in the above formula,we get

⇒ 220 = 2.2 × R

⇒ R = 220/2.2

⇒ R = 220 × 10 / 22

⇒ R = 2200 / 22

⇒ R = 100 ohms

Thus,the resistance of electric iron is 100 ohms.

P = I²R

★ putting the values in the above formula,we get

P = (2.2)² × 100

= 4.84 × 100

= 484/100 × 100

= 484 watts

Thus,the power of electric iron is 484 watts .

Answer 2

$\huge{\underline{\pink{\tt{Given,}}}}$

• A Electric Iron Draws 2.2 Amperes of Current.

• From 220 Volt (Potential Difference).

$\huge{\underline{\pink{\tt{To \ Find,}}}}$

• Resistance = ?
• Power = ?

$\huge{\underline{\pink{\tt{Formula\:Used:}}}}$

$\bigstar \boxed{\sf{Potential\:Difference = Current \times Resistance}}$

$\bigstar \boxed{\sf{Power = (Current)^{2} \times Resistance}}$

$\huge{\underline{\pink{\tt{Solution :}}}}$

$\bigstar$Firstly We know About Ohm's Law :

$\longmapsto$ This Law Define that Electric Current is Proportional to Potential Difference and Inversely Proportional to Resistance. That's simple means When Voltage Increase then Current will be Increase and When Resistance Increase then Current will be Decrease .

$\mapsto \boxed{\sf{Current = \dfrac{Potential\:Difference}{Resistance}}}$

$\mapsto \boxed{\sf{Resistance = \dfrac{Potential\:Difference}{Current}}}$

Now Solve this Question with the Help of this Law :

$\underline{\red{\mathfrak{First\:Case:}}}$

$\longrightarrow \boxed{\sf{V = IR}}$

$\longrightarrow \sf{220 = 2.2 \times R}$

$\longrightarrow \sf{R = \dfrac{220}{2.2}}$

$\longrightarrow \sf{R = \dfrac{2200}{22}}$

$\longrightarrow \boxed{\sf{R = 100\:ohms}}$(Answer)

Therefore, We have Now Resistance so We Use Second Formula to Find Power :

$\underline{\red{\mathfrak{Second\:Case:}}}$

$\longrightarrow \boxed{\sf{P = I^{2}R}}$

$\longrightarrow \sf{P = (2.2)^{2} \times 100}$

$\longrightarrow \sf{P = 4.84 \times 100}$

$\longrightarrow \boxed{\sf{P = 484\:Watts}}$ (Answer)

Therefore,

$\bigstar \boxed{\red{\mathfrak{Resistance = 100\:ohms \:And \: Power = 484\:Watts}}}$

$\rule{200}2$