Question

) An electric iron draws a current of 0.4 A when the voltage is 220 volt. Calculate the amount of electric charge flowing through it in two hours.

Answer 1

Answer :-

$\implies \boxed{ \sf{q \: (charge)= 2880} \: coulamb } \:$

To Find :-

→ Electric charge .

Explanation:-

Given that

• Electric current (i) = 0.4 A

• Potential (V) = 220 Volt

• Time (t) = 2 hours = 2×3600 second.

• Charge (q) = ?

We know that

$\implies \boxed{ \sf{electric \: current (i)= \frac{charge(q)}{time} }}$

substitute the given values

$\implies \sf{ 0.4 = \frac{q}{2 \times 3600} } \\ \\ \implies \sf{ \frac{4}{10} \times 2 \times 3600 = q \: } \\ \sf{ or \: } \\ \: \\ \implies \sf{ q = 8 \times 360 \: } \\ \\ \implies \boxed{ \sf{q = 2880} \: coulamb \: or \: ampere - second}$

hence electric charge of 2880 C flowing through electric iron in 2 hours .

What is current :-

→ The flowing of charge in conductor per unit time is known as current .

Its unit is Ampere .

Its dimension is [ A ]

Answer 2

Explanation:

Given -

An electric Iron draws a Current of 0.4 A when the voltage is 220 Volt

To Find -

Amount of electric charge flowing through it in Two hours.

Now,

As we know that :-

• I = Q/t

Given -

I = 0.4 A

V = 220 V

t = 2 hrs = 2 × 60 × 60 = 7200 seconds

• Q = I × t

» 0.4 × 7200

» 4 × 720

» 2880 C

Hence,

Amount of electric charge flowing through Electric Iron in Two hours is 2880 C.

Some related Questions :-

Q A current of 0.5 A drawn by a filament of an electric bulb for 10 minutes. Find the amount of electric charge that flows through the circuit.

Answer -

Given -

I = 0.5 A

t = 10 minutes = 10 × 60 = 600 seconds

As we know that :-

• Q = It

» 0.5 × 600

• » 300 C

Hence,

The amount of electric charge that flows through the circuit is 300 C

Additional information :-

• Here C represents Coulomb.
• The SI unit of charge is Coulomb (C).
• The electric current is expressed by a unit called ampere (A), named after the French scientist, Andre-Marie Ampere.