Question

An electric iron draws a current of 0.4 ampere when tge voltage is 220 volt calculate the amount of electric charge flowing through it in 2 hrs

Answer 1

Given that, An electric iron draws a current of 0.4 ampere when the voltage is 220 volt.

$\implies\:\sf{Current \:(I)\:=\:0.4A}$

$\implies\:\sf{Voltage\:(V) \: =\: 220V}$

We have to find the amount of electric charge (q) flowing through it in 2 hrs.

$\implies\:\sf{Time(t)\:=\:2\:hrs.}$

$\small{\sf{\:\:\:\:\:\:\:\:\:{\underline{We\:know\:that:}}}}$

$\underline{\boxed{\sf{Current\:=\:\frac{Charge}{Time}}}}$

$\small{\sf{\:\:\:\:\:\:\:\:\:{\underline{As\:per\:given\:data\:we\:have}}}}$

Electric Current of 0.4 A, Voltage of 220V and time 2 hours.

Substitute the values in the boxed formula

$\longrightarrow\:\sf{0.4\:=\:\frac{q}{2}}$

Convert the time (i.e. in hours) in seconds.

1 hour = 3600 seconds

2 hours = 2 × 3600 seconds

$\longrightarrow\:\sf{0.4\:=\:\frac{q}{2 \times 3600}}$

$\longrightarrow\:\sf{0.4 \times 2 \times 3600 \:=\:q}$

$\longrightarrow\:\sf{8 \times 360 \:=\:q}$

$\rightarrow\:\sf{2880C \:=\:q}$

Therefore,

The amount of electric charge flowing through it in 2 hrs is 2880C (coulomb).

Answer 2

$\tt{\huge{\purple{ .............. }}}$

QUESTION :

An electric iron draws a current of 0.4 ampere when the voltage is 220 volt .

Calculate the amount of electric charge flowing through it in 2 hours.

$\tt{\huge{\green{ .............. }}}$

SOLUTION :

From the above Question, we can gather the following information ..

An electric iron draws a current of 0.4 ampere when the voltage is 220 volt .

So, Voltage = 220 V, I = 0.4 A

We have to calculate the amount of electric charge flowing through it in 2 hours.

So, the given time is 2 hours, which is equal to 2 × 3600 Seconds = 7200 Seconds.

Now,

We know that Q = it

Where Q is the charge.

I is the current flowing in the circuit.

t is the time, .

So, Q = 0.4 × 7200 Culombs

=> Q = 720 × 4 = 2880 Culombs

This is the required answer...

The required amount of charge flowing through that iron in 2 hours is 2880 Culombs.

ANSWER :

The required amount of charge flowing through that iron in 2 hours is 2880 Culombs.