Question

An electric iron draws a current of 2.2 A from 220v supply. what current will this electric iron draw when connected to 110v supply.​

Answer 1

Answer:

• 1.1 is the required Current.

Explanation:

Given:-

• Current ,I = 2.2 A
• Potential Difference ,V = 220 v
• Potential Difference ,V' = 110 v

To Find:-

• Current when connected to 110v ,I'

Solution:-

Firstly we calculate the Resistance of electric iron . Using Ohm's Law

• V = IR

where,

• V denotes Potential Difference
• I denote Current
• R denote Resistance

Substitute the value we get

→ 220 = 2.2 × R

→ R = 220/2.2

→ R = 2200/22

→ R = 100 Ω

Resistance of electric iron is 100 ohms.

Now, Calculating the New Current when electric iron is connected in 110v . Using Ohm's Law

• V' = I' R

substitute the value we get

→ 110 = I' × 100

→ I' = 110/100

→ I'= 1.1 A

• Hence, the new current of the electric iron is 1.1 Ampere .

Answer 2

Answer:

Given :-

• Current = 2.2 A
• Potential difference (V)= 220 V
• Potential difference (V') = 110 V

To Find :-

Current (I')

Solution :-

Firstly let's find out resistance of iron.

$\huge \fbox{V = IR}$

Here,

V is the potential difference

I is the current

R is the Resistance

$\tt \: 220 = 2.2 \times R$

$\tt \: \dfrac{220}{2.2} = R$

$\tt \:R = 100$

Resistance of Iron is 100 ohm

Now,

We will calculate the new iron current.

$\huge \fbox{V' = I'R}$

$\tt \: 110 = I' \times 100$

$\tt \dfrac{110}{100} = I'$

$\tt \: I' = 1.1 \: ampere$

Hence :-

The new current is 1.1 Ampere.