Question

An electric iron draws a current of 3.4 A
from the 220 V supply line. The current
that electric iron draws when connected
to 110 V supply line​

Answer 1

Explanation:

$For \: an \: electric \: iron-$

$electric \: current (I) = 3.4 A$

$supplied \: potential(V) = 220 volt$

$resistance (R) = \frac{V}{I}$

$R =\frac{220}{3.4}$

$When \: this \: iron \: is \: connected \: to$

$110v \: potential$

$then , current(I) =\frac{V}{R}$

$I =\frac{110}{(\frac{220}{3.4})}$

$I =\frac{110 × 3.4}{220}$

$I = \frac{3.4}{2}$

$I = 1.7 A$