English, asked by profile94, 2 months ago

An electric iron draws a current of 4 A when connected to a 200 supply. Find the resistance of the heat element of an electric iron. What current would the iron draw when it is
connected to a 240 V supply?​

Answers

Answered by anudeepthipanda2011
1

Explanation:

••What is Ohm's law an electric iron draws a current of 3.4 A from the 220 V supply line what currents will this electric iron draws when connected to 110 V supply line?

Answer--Thus, the electric iron will draw a current of 1.7 amperes from 110 volt supply line

••What is the resistance of an electric iron which draws a current of 4 A when connected to a 220 V mains?

Answer-∴ Resistance R=IV=4220=55Ω

••What is the heating element of electric iron made of?

Answer-Nichrome

Nichrome is used as a heating element in an electric iron . It is an 80 percent nickel and 20 percent chromium alloy with nickel and chromium. It has a high melting point of 1400 degrees C.

I hope you understand my point

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Answered by Anonymous
1

Given :

  • Potential difference, V = 200 V
  • Current, I = 0.4 A

To Find :

  • Resistance of the heat element of an electric iron, R = ?
  • Current of the iron when it is connected to 240 V supply = ?

Solution :

As, we have :

  • Potential difference, V = 200 V
  • Current, I = 0.4 A

So, to find resistance we have a formula :

\bull \: \: \: \: \: \underline{ \boxed{ \bf \pink{I = \dfrac{V}{R}}}} \: \: \pink{ \dag}

By substituting values :

 \sf :  \implies 0.4 =  \dfrac{200}{R}  \\  \sf :  \implies R =  \dfrac{200}{0.4}  \:  \:  \\   \:  \:  \:  \:  \:  \: \sf :  \implies R =  500 \: ohm

 \underline{ \tt Hence,  \: Resistance = \pink{ \bf 500  \: ohm}}

Now, if potential difference is changed from 200 V to 240 V, then current will also be changed.

  • V' = 240 V
  • I' = ?

\bull \: \: \: \: \: \underline{ \boxed{ \bf \pink{I' = \dfrac{V'}{R}}}} \: \: \pink{ \dag}

 \sf :  \implies I' =  \dfrac{240 }{500} \:  \:  \:   \\  \sf :  \implies I' =  0.48A

 \underline{ \tt Hence,  \: new \: current = \pink{ \bf 0.48  \: A}}

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