An electric iron draws a currunt of 3.4 amphere from the 220 volt supply line.what currunt will this electric iron draws when connected to 110 volt supply line.
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say the current is when connected to supply, setup a proportion using ohm's law and solve
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I = 3.4 Amp
V = 220 Volts
Electric iron has a resistance = R
V = I R
=> R = V / I = 220 / 3.4
= 64.7 Ω
When the electric iron is connected to a 110 Volts supply,
I = V / R = 110 / 64.7 = 1.7 Amp.
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Alternately, As the voltage becomes half of its value, the current becomes half of its value, as the current is directly proportional to the potential difference across a conductor or a resistor. This is as per Ohm's law.
V = 220 Volts
Electric iron has a resistance = R
V = I R
=> R = V / I = 220 / 3.4
= 64.7 Ω
When the electric iron is connected to a 110 Volts supply,
I = V / R = 110 / 64.7 = 1.7 Amp.
================
Alternately, As the voltage becomes half of its value, the current becomes half of its value, as the current is directly proportional to the potential difference across a conductor or a resistor. This is as per Ohm's law.
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