an electric iron draws current of 0.5A when voltage is 200v. calculate the amount of change following through it in 1 hr.
Answers
Answered by
1
we that
i=q÷t
so that
0.5=q÷1 hour
0.5 = q÷3600 second
therefore
q = 0.5×3600
q = 1800 coulomb
charge = 1800 coulomb
i=q÷t
so that
0.5=q÷1 hour
0.5 = q÷3600 second
therefore
q = 0.5×3600
q = 1800 coulomb
charge = 1800 coulomb
Similar questions
English,
8 months ago
Physics,
8 months ago
Math,
1 year ago
Social Sciences,
1 year ago
Math,
1 year ago