Question

an electric iron is used on 240 voltage supply and draws a current of 4 ampere 1what is its power.
2 what is its resistance
3 what is the cost of using the iron for the of january 10 hours a day if 1kWh costs Rs. 3.40​

Answer 1

V=240V

I=4A

P=V×I

P=240×4

•P= 960 W

from ohms law

V=I×R

V/I=R

240/4=R

•Resistance=60 ohm

now , Electrical energy=P×T

electrical energy = 960/1000 ×10 kwh

electrical energy=9.6KWh

again,1kwh costs-------₹3.40

9.6 kwh costs -----₹ 3.40×9.6

•9.6 kwh costs ₹32.64*31= rs 1011.84

Answer 2

Answer:

Power 240×4= 960Watt

Resistance 240÷4= 60 Ohm