Question

An electric iron is used on a 240V supply and draws a current of 4 Ampere. 
What is the cost of using the iron for the month of January 10 hours a day if 1kwh costs Rs 3.40 ?

Answer 1

Hey mate ^_^

=======
Answer:
=======

$P = IV$

$P = 4A × 240V$

Therefore,

$P = 960W$

$V = RI$

$R = 60Ω$

Now,

Energy used = $\frac{(Power × Time)}{1000}$

$= \frac{960×10}{1000}$

$= 96 kWh$

Cost of using iron = Energy × Cost per kWh

$= 96 × 3.40$

$= 326.40$

Therefore,

Final answer: $Rs. 326.40$

#Be Brainly❤️

Answer 2

P=IV 

P = 4A × 240VP=4A×240V 

Therefore, 

P = 960WP=960W 

V = RIV=RI 

R = 60ΩR=60Ω 

Now, 

Energy used = \frac{(Power × Time)}{1000}1000(Power×Time)​ 

= \frac{960×10}{1000}=1000960×10​ 

= 96 kWh=96kWh 

Cost of using iron = Energy × Cost per kWh

= 96 × 3.40=96×3.40 

= 326.40=326.40 

Therefore, 

Final answer: Rs. 326.40Rs.326.40 

#Be Brainly❤️