Question

An electric iron of 1100 W is
operated for 2 hrs daily. What will
be the electrical consumption
expenses for that in the month of
April? (The electric company
charges Rs 5 per unit of energy).
Da
D220​

Answer 1

Answer:

Correct Framed Question:-

An electric iron of 1100 W is operated for 2 hrs daily. What will be the electrical consumption expenses for that in the month of April? (The electric company charges Rs 5 per unit of energy).

Answer:-

Given that:-

• Time 2 hours
• Power 1100 Watts
• We need the bill of the electric energy used.

Concept:-

We need

$\sf{P = VI}$

Let's Do!

First, converting Watt to Kilowatt:-

1100/1000= 1.1 Kw

Now, converting to Kwh ,

1.1 × 2 = 2.2 Kwh

Now, we are given :-

1 Unit = Rs. 5

2.2 Units = 2.2 × 5

= Rs. 11 is the final Bill price .

For 1 month,

We would consider it as 30 days.

So, 11×30 = Rs. 330 is the Bill for the whole Month.

Remember:-

• Unit and Kwh or Kilowatt hour are same.
• For month, we take 30 days as the total days.
• Complications may occur if we consider it as 31 days unless stated.

Answer 2

Given

• An electric iron of 1100 W is operated for 2 hrs daily.

We Find

• The electrical consumption expenses for that in the month of April ( The electric company charges Rs 5 per unit of energy )

We knows

P = VI

According to the question

First, converting Watt to Kilowatt:-

1100/1000= 1.1 Kw

Now, converting to Kwh ,

1.1 × 2 = 2.2 Kwh

Now we Know that ,

1 Unit = Rs. 5

2.2 Units = 2.2 × 5

= Rs. 11 is the final Bill price .

According to the case For 1 month ( convert into as 30 days )

So,

= 11×30 = Rs. 330

Rs. 330 is the Bill for the whole Month.

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