Question

An electric iron of 1100 w is operated for 2 hrs daily what will be the electrical consumption expenses for that in the month of april

Answer 1

Power=1100 W=1.1 kW

Time= 2 hrs

Energy consumed per day=Power*Time

                                           =1.1*2

                                           =2.2 kWh

Energy consumed in April=Energy consumed per day*30

                                           =2.2*30

                                           =66 kWh