Question

An electric iron of 1100 W is operated for 2hrs daily.What will be the electrical consumption expenses that in the month of April?( the electric company charges Rs 5 per unit of changes)​

Answer 1

Answer:

I hope My answer is Useful though my handwriting is tooo bad and I am sorry for that

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Answer 2

Answer:

1unit= 1kwh

1kwh= 1000w per hour

therefore we will convert 1100w into kw first.

i.e 1100/1000 .

now time in hours is 2 hours.

No. of days in April= 30

therefore..total energy in kWh

= (energy consumed in kw) x (time in hours) x ( no. of days)

= 1100/ 1000 x 2 x 30

= 66 units.

1unit = rs. 5

total money = 66 x 5= Rs. 330

hope it helps..