an electric iron of 1100 watt is operated for 2 hours daily what will be the electric consumption expenses for that in the month of February 2016.
(the electric company charges Rd.5per unit of energy)
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Answer:
58 hrs should be electric consumption expenses
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Power consumed =1100 watt= 1.1KW
Time = 2hrs per day
No. of days = 29 (2016 was leap year)
Total time= 29 x 2=58hrs
Energy= power x time
or, Energy= 1.1KW x 58hrs
= 63.8KWh
1KWh =1 unit
1unit=5 Rs
63.8Units=5x63.8
=319Rs
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