Question

an electric iron of 1100W is operated for 2 hrs daily. what will be the electrical consumption expenses for that in the month of April? (the electric company charges Rs 5 per unit of energy).with explanation please

Answer 1

hey friend !!!!!
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your answer is "330"

Explainatioan
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Energy = 1100W = 1.1Kw

Energy=power*time=1.1(kw)*2(hr)=2.2kwh

Energy used in a day=2.2 unit

Energy used in 30 days= 2.2×30unit = 66unit

Total cost=66×5=330 rs

hope it will help you..

Answer 2

This is the easy way to understand this sum

Given.

P=1100w=1.1kwh (convert w into kwh)

Time=2hrs

To find

Cost to spend time for april=?

Solution

Work=p×t

=1.1×2

Work done to spend time for 1 day = 2.2kwh=2.2 units

Energy consumed in 1 day = work done in 1 day

Energy consumed in 1 day = 2.2units

Cost to operate for 1 day × rate of units consumed in 1 day

=2.2×5

=Rs 11

Cost to operate for April

=cost To operate for 1 day × 30

=11×30

=Rs 330