An electric iron of 1250w is used for 3h per day. The energy consumed in one day by the electric iron is how much units.
Answers
Answered by
7
Answer:
3.75 units
Explanation:
Energy consumed = 1250 X 3 = 3750 W.h = 3.75 kWh = 3.75 units
Answered by
6
Answer:
The energy consumed in one day by the electric iron = 3.75 units
Explanation:
As per the given data of question,
We have,
Power of an electric iron = 1250 Watt
As we know that 1 K-watt = 1000 watt.
∴ Power = 1.25 Kw
Per day consumption time = 3 h
Since, energy consumption in units is equal to power in kw multiplied by time in hours that is,
1 kw-h = 1 unit
∴ The energy consumed in one day by the electric iron is
= 1.25 kw × 3 h
= 3.75 kw-h
= 3.75 units
Hence, energy consumed in one day by the electric iron = 3.75 units.
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