Question

an electric iron of power 1.5 kilowatt is used for 30 minutes to press the clothes calculate the electrical energy consumed in kilowatt hour and joule

Answer 1

electrical energy = power x time

                            = 1.5 kw x 0.5 h = 0.75 KwH

                                                       = 0.75 x 3.6 x 10^6 J

                                                        = 2.7 x 10^6 J

Answer 2

The electrical energy consumed is 0.75 kWh or $27\times 10^5\ J$.

Explanation:

It is given that,

Power of the electric power, P = 1.5 kW

Time, t = 30 min = 0.5 h

To find,

The electrical energy consumed in kilowatt hour and joule.

Solution,

We need to find the electrical energy consumed by the electric iron. Electric power is defined as the electrical energy per unit time. It is given by :

$P=\dfrac{E}{t}$

E is the electrical energy

$E=P\times t$

$E=1.5\ kW\times 0.5\ h$

E = 0.75 kWh

Since, $1\ kWh=3.6\times 10^6\ J$

Energy, $E=27\times 10^5\ J$

So, the electrical energy consumed is 0.75 kWh or $27\times 10^5\ J$.

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