Question

An electric iron of power 1.5kW is used for 30 min to press clothes Calculate the electrical energy consumed in (a)kilowatt hour (b) joule
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Answer 1

Answer:

Power=w/t

electrical energy W=P×T

a)P=1.5kW

time=30 minutes=1/2HOUR

w= 1/5 ×1/2 = 0.75kwh

b)1kWh= 3.6 × 10^6J

therefore 75kzwh = 0,75 × 3.6 × 10^6

2.700× 10^6

2.7 × 10^6 J

Answer 2

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Answer:-

The electrical energy consumed in 0.75kWh or 27×10⁵ J.

Explanation:-

It is given that,

Power of the electric power, P =1.5kW

Time, t = 30 min =0.5h

To find,

The elecrical energy consumed in kilowatt hour and joule.

Solution,

We need to find the electrical energy consumed by the electric iron . Electric power is defined as electrical energy per unit time. It is given by:

P =E/t

E is the Electrical energy.

E = P × t

E = 1.5kW × 0.5h

E =0.75kWh

Since,1kWh = 3.6 × 10⁶ J

Energy, E = 27 × 10⁵ J

So the electrical energy consumed is 0.75 kWh or 27 × 10⁵ J.

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