An electric iron of resistance 20 12 takes a current of 5 A. Calculate the
heat developed in 30 s.
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Appropriate Question :
An electric iron of resistance 20 Ω takes a current of 5 A. Calculate the heat developed in 30 s.
Required Answer :
♦ Heat developed in the conductor in 30 seconds = 15,000 J
Given :
→ Resistance of an electric iron = 20 Ω
→ Current = 5 A
→ Time = 30 s
To find :
→ The heat developed in 30 seconds.
Solution :
Formula to find the heat developed in a conductor :-
- H = I²Rt [Joule's equation of electric heating.]
where,
- H denotes the heat developed.
- I denotes the current in the conductor.
- R denotes the resistance.
- t denotes the time.
we have,
- I = 5 A
- R = 20 Ω
- t = 30 s
Substituting the given values :-
→ Heat developed = (5)²(20)(30)
→ Heat developed = 5 × 5 × 20 × 30
→ Heat developed = 15,000
Therefore, the heat developed = 15,000 J
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Some related formulae :-
- I = Q ÷ T
- Q = I × T
- V = I × R
- R = V ÷ I
where,
- I denotes the current.
- Q denotes the charge.
- T denotes the time.
- V denotes the potential difference.
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