an electric iron of resistance 20 ohm take a current of 5 ampere calculate the heat developed in 30 second
Answers
Answered by
19
Given-
current (I) -5A
resistence (R)-20 ohm
time(T)-30 s
To find-
heat- ?
We know that-
H= I^2 ×R×T
H=5^2×20×30
H=25×20×30
H=15000 joule.
current (I) -5A
resistence (R)-20 ohm
time(T)-30 s
To find-
heat- ?
We know that-
H= I^2 ×R×T
H=5^2×20×30
H=25×20×30
H=15000 joule.
shivjot27:
hii
Answered by
26
Hey mate ^_^
=======
Answer:
=======
Given:
Resistance(R) = 20 Ω
Electric current (I)= 5 A
Time(t)= 30 s
Now,
H = I^2 Rt
= 5 × 5 × 20 × 30
= 15000 J
= 1.5 × 10^4J
∴ The heat developed in 30s is 1.5×10^4J
#Be Brainly❤️
=======
Answer:
=======
Given:
Resistance(R) = 20 Ω
Electric current (I)= 5 A
Time(t)= 30 s
Now,
H = I^2 Rt
= 5 × 5 × 20 × 30
= 15000 J
= 1.5 × 10^4J
∴ The heat developed in 30s is 1.5×10^4J
#Be Brainly❤️
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