Question

An electric iron of resistance 20 ohm takes a current of 5 ampere. Calculate the heat developed in 30s

Answer 1

Explanation:

R=50ohn, I=5A , T=30sec

Q=?

$q = {i}^{2} rt$

$= {5}^{2} \times 20 \times 30$

=25×20×30

=15,000q Answer.

Answer 2

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