An electric iron of resistance 20 ohm takes a current of 5 A. Calculate the electric power
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Explanation:
Given that Resistance(R) = 20 Ω, Electric current (I)= 5 A and time(t)= 30 s
Now we know that H= I2Rt
= 5×5×20×30
= 15000J=1.5×104J
∴ The heat developed in 30s is 1.5×104J
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