Question

An electric iron of resistance 20 ohm takes a current of 5a calculate the heat developed in 5 sec

Answer 1

Solution :

⏭ Given:

✏ Resistance of iron = 20 Ω

✏ Current flow = 5A

✏ Time interval = 5s

⏭ To Find:

✏ Heat energy developed in iron during given time interval

⏭ Formula:

✏ Formula of heat energy in terms of current flow, resistance and time interval is given by...

$\bigstar \: \boxed{ \tt{ \large{\pink{H = {I}^{2} Rt}}}} \: \bigstar$

⏭ Terms indication:

• H denotes heat energy
• I denotes flow of current
• R denotes resistant
• t denotes time interval

⏭ Calculation:

$\twoheadrightarrow \sf \: H = {5}^{2} \times 20 \times 5 \\ \\ \dashrightarrow \sf \: H = 25 \times 20 \times 5 \\ \\ \twoheadrightarrow \: \boxed{ \tt{ \red{ \huge{H = 2500 \: J}}}} \: \bigstar$

Answer 2

Answer:

Heat developed = 2.5 KJ

Explanation:

Heat developed , H = I²Rt

given:

R = 20Ω   ,      I = 5 A    ,   t = 5 s  .

so, H = 25*20*5

H = 2500 J  = 2.5 KJ