An electric iron of resistance 20 ohms take a current of 5 ampere calculate the heat developed in 30 second
Answers
Answered by
3
according to joule's law of heating,
H=I²RT
where I=current
R=resistance
T=time
therefore H=5²×20×30
=25×600
=15000 joules
H=I²RT
where I=current
R=resistance
T=time
therefore H=5²×20×30
=25×600
=15000 joules
Answered by
2
Given :-
R = 20 Ω
I = 5 A
t = 30 s
H = I^2Rt
= (5)^2×20×30
= 15000 J
= 1.5 × 10^4 J
Similar questions