Question

An electric iron of resistance 20 ohms takes a currrent of 5 amp. Calculate heat developed in 30 s

Answer 1

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(R) = 20 Ω

(I)= 5 A

(t)= 30 s

Now we know that H= I2Rt

                         use it here     = 5×5×20×30

                                = 15000J=1.5×104J

The heat developed in 30s is 1.5×104J

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