Question

an electric iron of resistance 20 takes a current of 5A. calculate the heat developed in 30 s​

Answer 1

Answer:

resistance= 20ohm

current= 5A

time = 30s

formula = l^2rt

25×20×30

15000 J

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Answer 2

Explanation:

Given that,

Resistance=20Ω

Electric current (I)=5A

Time (T)=30s

Now we know that H= $I^{2}$Rt

5×5×20×30

15000J=1.5J×$10^{4}$

-The heat developed in 30 s is 1.5×$10^{4}$J

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