Question

An electric iron of resistance 200 ohm take a current of 5 ampere.Calculate the heat develop in 30 second

Answer 1

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(R) = 200 Ω

(I)= 5 A

(t)= 30 s

Now we know that H= I2Rt

use it here = 5×5×200×30

The heat developed in 30s is 150000 j

Answer 2

Explanation:

H=i^2RT

= 25×200×30

= 150000

= 1.5×10^5joule